differentiation

Question: $\frac{d}{{dx}}\sqrt {\frac{{1 - \sin 2x}}{{1 + \sin 2x}}} = $

1) ${\sec ^2}x$ (b)$ - {\sec ^2}\left( {\frac{\pi }{4} - x} \right)$

2) ${\sec ^2}\left( {\frac{\pi }{4} + x} \right)$

3) ${\sec ^2}\left( {\frac{\pi }{4} - x} \right)$

Solution:

Explanation: Explanation

standard-differentiation

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