magnetism

Question: A bar magnet of length 10 cm and having the pole strength equal to $10^{–3}$ weber is kept in a magnetic field having magnetic induction (B) equal to $4\pi \times {10^{ - 3}}$ Tesla. It makes an angle of $30^o$ with the direction of magnetic induction. The value of the torque acting on the magnet is (${\mu _0} = 4\pi \times {10^{ - 7}}weber/amp \times m$)



1) $2\pi \times {10^{ - 7}}N \times m$
2) $2\pi \times {10^{ - 5}}N \times m$
3) $0.5N \times m$
4) $0.5 \times {10^2}N \times m$
Solution: Explanation: No Explanation
Magnet and It's Properties

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