If $y = {\sin ^{ - 1}}(x\sqrt {1 - x} + \sqrt x \sqrt {1 - {x^2})} ,$then $\frac{{dy}}{{dx}} = $

Question

If $y = {\sin ^{ - 1}}(x\sqrt {1 - x}  + \sqrt x \sqrt {1 - {x^2})} ,$then $\frac{{dy}}{{dx}} = $

Accepted Answer

$\frac{1}{{\sqrt {1 - {x^2}} }} + \frac{1}{{2\sqrt {x - {x^2}} }}$

Answer

$\frac{{ - 2x}}{{\sqrt {1 - {x^2}} }} + \frac{1}{{2\sqrt {x - {x^2}} }}$

Answer

$\frac{{ - 1}}{{\sqrt {1 - {x^2}} }} - \frac{1}{{2\sqrt {x - {x^2}} }}$

Answer

None of these

differentiation