Moving Charges and Magnetism

Question: The relation between voltage sensitivity (${\sigma _V}$) and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = G)

1) $\frac{{{\sigma _i}}}{G} = {\sigma _V}$

2) $\frac{{{\sigma _{_V}}}}{G} = {\sigma _i}$

3) $\frac{G}{{{\sigma _V}}} = {\sigma _i}$

4) $\frac{G}{{{\sigma _i}}} = {\sigma _V}$

Solution:

Explanation: No Explanation

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