Moving Charges and Magnetism

Question: A proton enters a magnetic field of flux density $1.5\,weber/{m^2}$ with a velocity of $2 \times {10^7}\,m/\sec $ at an angle of $30^\circ $ with the field. The force on the proton will be

1) $2.4 \times {10^{ - 12}}\,N$

2) $0.24 \times {10^{ - 12}}\,N$

3) $24 \times {10^{ - 12}}\,N$

4) $0.024 \times {10^{ - 12}}\,N$

Solution:

Explanation: No Explanation

Motion of Charged Particle In Magnetic Field

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