Electrostatics

Question: Two charges $ + 3.2 \times {10^{ - 19}}C$ and $ - 3.2 \times {10^{ - 9}}C$ kept $2.4 \AA$ apart forms a dipole. If it is kept in uniform electric field of intensity $4 \times {10^5}volt/m$ then what will be its electrical energy in equilibrium

1) $ + 3 \times {10^{ - 23}}J$

2) $ - 3 \times {10^{ - 23}}J$

3) $ - 6 \times {10^{ - 23}}J$

4) $ - 2 \times {10^{ - 23}}J$

Solution:

Explanation: Explanation

electric-dipole

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