Categories > Moving Charges and Magnetism > Biot-Savart's Law > Two concentric coils each of radius equal to $2\pi {\rm{ }}cm$ are placed at right angles to each other. 3 ampere and 4 ampere are the currents flowing in each coil respectively. The magnetic induction in $Weber/{m^2}$ at the centre of the coils will be $({\mu _0} = 4\pi \times {10^{ - 7}}Wb/A.m)$

Moving Charges and Magnetism

Question: Two concentric coils each of radius equal to $2\pi {\rm{ }}cm$ are placed at right angles to each other. 3 ampere and 4 ampere are the currents flowing in each coil respectively. The magnetic induction in $Weber/{m^2}$ at the centre of the coils will be $({\mu _0} = 4\pi \times {10^{ - 7}}Wb/A.m)$


1) $5 \times {10^{ - 5}}$
2) $7 \times {10^{ - 5}}$
3) $12 \times {10^{ - 5}}$
4) ${10^{ - 5}}$
Solution: Explanation: No Explanation
Biot-Savart's Law Amperes Law

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