Categories > Moving Charges and Magnetism > Biot-Savart's Law > A straight section PQ of a circuit lies along the X-axis from $x = - \frac{a}{2}$ to $x = \frac{a}{2}$ and carries a steady current i. The magnetic field due to the section PQ at a point X = + a will be

Moving Charges and Magnetism

Question: A straight section PQ of a circuit lies along the X-axis from $x = - \frac{a}{2}$ to $x = \frac{a}{2}$ and carries a steady current i. The magnetic field due to the section PQ at a point X = + a will be


1) Proportional to a
2) Proportional to ${a^2}$
3) Proportional to $1/a$
4) Zero
Solution: Explanation: No Explanation
Biot-Savart's Law Amperes Law

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