Questions in vectors

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	The vector sum of two forces is perpendicular to their vector differences. In that case, the forces
	y component of velocity is 20 and x component of velocity is 10. The direction of motion of the body with the horizontal at this instant is
	Two forces of 12 N and 8 N act upon a body. The resultant force on the body has maximum value of
	Two equal forces (P each) act at a point inclined to each other at an angle of 120°. The magnitude of their resultant is
	The vectors $5\hat i + 8\hat j$ and $2\hat i + 7\hat j$are added. The magnitude of the sum of these vector is
	Two vectors $\vec A\,{\rm{ and }}\vec B$ are such that $\vec A + \vec B = \vec A - \vec B$. Then
	If a vector $2\hat i + 3\hat j + 8\hat k$is perpendicular to the vector $4\hat j - 4\hat i + \alpha \hat k$. Then the value of $\alpha $ is
	If two vectors $2\hat i + 3\hat j - \hat k$ and $ - 4\hat i - 6\hat j - \lambda \hat k$ are parallel to each other then value of $\lambda $ be
	A body, acted upon by a force of 50 N is displaced through a distance 10 meter in a direction making an angle of 60° with the force. The work done by the force be
	A particle moves from position $3\hat i + 2\hat j - 6\hat k$ to $14\hat i + 13\hat j + 9\hat k$ due to a uniform force of $(4\hat i + \hat j + 3\hat k)\,N.$ If the displacement in meters then work done will be