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The position vector of a particle is determined by the expression $\vec r = 3{t^2}\hat i + 4{t^2}\hat j + 7\hat k$. The distance traversed in first 10 sec is
Unit vector parallel to the resultant of vectors $\vec A = 4\hat i - 3\hat j$and $\vec B = 8\hat i + 8\hat j$will be
The component of vector $A = 2\hat i + 3\hat j$along the vector $\hat i + \hat j$is
The angle between the two vectors $\vec A = 3\hat i + 4\hat j + 5\hat k$ and $\vec B = 3\hat i + 4\hat j - 5\hat k$ will be
There are two force vectors, one of 5 N and other of 12 N at what angle the two vectors be added to get resultant vector of 17 N, 7 N and 13 N respectively
If $\overrightarrow A = 4\hat i - 3\hat j$ and $\overrightarrow B = 6\hat i + 8\hat j$ then magnitude and direction of $\overrightarrow A \, + \overrightarrow B $ will be
A truck travelling due north at 20 m/s turns west and travels at the same speed. The change in its velocity be
If the sum of two unit vectors is a unit vector, then magnitude of difference is
$\overrightarrow A = 2\hat i + \hat j,\,B = 3\hat j - \hat k$ and $\overrightarrow C = 6\hat i - 2\hat k$. Value of $\overrightarrow A - 2\overrightarrow B + 3\overrightarrow C $ would be
An object of m kg with speed of v m/s strikes a wall at an angle $\theta$ and rebounds at the same speed and same angle. The magnitude of the change in momentum of the object will beQuestion Image

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