Questions in vectors-m

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	If P and Q be the middle points of the sides BC and CD of the parallelogram ABCD, then $\overrightarrow{AP}+\overrightarrow{AQ}=$
	P is a point on the side BC of the $\Delta \,ABC$ and Q is a point such that $\overrightarrow{PQ}$ is the resultant of $\overrightarrow{AP},\,\overrightarrow{PB},\,\overrightarrow{PC}.$ Then ABQC is a
	In the figure, a vector x satisfies the equation $\mathbf{x}-\mathbf{w}=\mathbf{v}$ . Then x =
	A vector coplanar with the non-collinear vectors $\mathbf{a}$ and $\mathbf{b}$ is
	If ABCD is a parallelogram, $\overrightarrow{AB}=2\,\mathbf{i}+4\,\mathbf{j}-5\,\mathbf{k}$ and $\overrightarrow{AD}=\,\mathbf{i}+2\,\mathbf{j}+3\,\mathbf{k},$ then the unit vector in the direction of BD is
	If a, b and c be three non-zero vectors, no two of which are collinear. If the vector $\mathbf{a}+2\mathbf{b}$ is collinear with c and $\mathbf{b}+3\mathbf{c}$ is collinear with a, then ($\lambda $ being some non-zero scalar) $\mathbf{a}+2\mathbf{b}+6\mathbf{c}$ is equal to
	If $\mathbf{a}=2\mathbf{i}+5\mathbf{j}$ and $\mathbf{b}=2\mathbf{i}-\mathbf{j},$ then the unit vector along $y=0$ will be
	What should be added in vector $\mathbf{a}=3\mathbf{i}+4\mathbf{j}-2\mathbf{k}$ to get its resultant a unit vector $\mathbf{i}$
	If $\mathbf{a}=\mathbf{i}+2\mathbf{j}+3\mathbf{k},\,\,\,\mathbf{b}=-\mathbf{i}+2\mathbf{j}+\mathbf{k}$ and $\mathbf{c}=3\mathbf{i}+\mathbf{j},$ then the unit vector along its resultant is
	In a regular hexagon ABCDEF, $\overrightarrow{AE}=$