Questions in trigonometry

Select	Question
	$\tan 5x\tan 3x\tan 2x=$
	If $\tan \alpha $ equals the integral solution of the inequality $4{{x}^{2}}-16x+15<0$ and $\cos \beta $ equals to the slope of the bisector of first quadrant, then $\sin (\alpha +\beta )\sin (\alpha -\beta )$is equal to
	$\tan \frac{2\pi }{5}-\tan \frac{\pi }{15}-\sqrt{3}\tan \frac{2\pi }{5}\tan \frac{\pi }{15}$ is equal to
	The value of $\cos 12{}^\circ +\cos 84{}^\circ +\cos 156{}^\circ +\cos 132{}^\circ $ is
	The value of $\cos 52{}^\circ +\cos 68{}^\circ +\cos 172{}^\circ $ is
	$\frac{\cos 17{}^\circ +\sin 17{}^\circ }{\cos 17{}^\circ -\sin 17{}^\circ }=$
	$\frac{\cos 9{}^\circ +\sin 9{}^\circ }{\cos 9{}^\circ -\sin 9{}^\circ }=$
	$\frac{\sin 70{}^\circ +\cos 40{}^\circ }{\cos 70{}^\circ +\sin 40{}^\circ }=$
	If $\cos (A-B)=\frac{3}{5}$ and $\tan A\tan B=2,$ then
	$\tan 100{}^\circ +\tan 125{}^\circ +\tan 100{}^\circ \tan 125{}^\circ =$