Questions in thermodynamics

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	At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume$\gamma =1.41$. The work done on gas will be
	For adiabatic process, wrong statement is
	A diatomic gas initially at 18°C is compressed adiabatically to one-eighth of its original volume. The temperature after compression will be
	A gas is being compressed adiabatically. The specific heat of the gas during compression is
	The process in which no heat enters or leaves the system is termed as
	Two moles of an ideal monoatomic gas at ${{27}^{o}}C$ occupies a volume of V. If the gas is expanded adiabatically to the volume $2V,$ then the work done by the gas will be $[\gamma =5/3,\,R=8.31J/mol\,K]$
	At ${{27}^{o}}C$ a gas is suddenly compressed such that its pressure becomes $\frac{1}{8}th$ of original pressure. Temperature of the gas will be $(\gamma =5/3)$
	$\Delta U+\Delta W=0$ is valid for
	An ideal gas at a pressures of 1 atmosphere and temperature of ${{27}^{o}}C$ is compressed adiabatically until its pressure becomes 8 times the initial pressure, then the final temperature is ($\gamma = 3/2$)
	Air is filled in a motor tube at ${{27}^{o}}C$ and at a pressure of $8$ atmospheres. The tube suddenly bursts, then temperature of air is $[\text{Given}\,\,\gamma \,\text{of}\,\text{air}=\,1.5]$