Questions in solutions

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	How many grams of a non-volatile solute having a molecular weight of 90 are to be dissolved in 97.5 g water in order to decrease the vapour pressure of water by 2.5 percent
	The vapour pressure of benzene at 90°C is 1020 torr. A solution of 5 g of a solute in 58.5 g benzene has a vapour pressure of 990 torr. The molecular weight of the solute is
	The diagram given below is a vapour pressure composition diagram for a binary solution of A and B. In the solution A-B interactions are
	V.P. of pure A $P_{A}^{0}=100\,mm\,Hg$, V.P. of pure B $P_{B}^{0}=150\,mm\,Hg$ Distillate of vapours of a solution containing 2 mol of A and 3 mol of B will have total vapour pressure, approximately, on condensation
	Mixture of volatile components A and B has total vapour pressure (in torr)$P=254-119{{x}_{A}}$, where ${{x}_{A}}$ is mole fraction of A in mixture. Hence $p_{A}^{0}$and $p_{B}^{0}$are (in torr)
	The vapour pressure of a dilute aqueous solution of glucose is 750 mm of mercury at 373 K. The mole fraction of solute is
	The temperature at which the vapour pressure of a liquid becomes equal to the atmospheric pressure is known as
	Which of the following will have the highest boiling point at $1\ atm$ pressure
	0.01 molar solutions of glucose, phenol and potassium chloride were prepared in water. the boiling points of
	Which one has the highest boiling point