Questions in rotational-motion

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A solid sphere (mass 2 M) and a thin hollow spherical shell (mass M) both of the same size, roll down an inclined plane, then
A hollow cylinder and a solid cylinder having the same mass and same diameter are released from rest simultaneously from the top of an inclined plane. Which will reach the bottom first
The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height h, from rest without sliding, is
A solid cylinder rolls down an inclined plane from a height h. At any moment the ratio of rotational kinetic energy to the total kinetic energy would be
An inclined plane makes an angle of ${{30}^{o}}$ with the horizontal. A solid sphere rolling down this inclined plane from rest without slipping has a linear acceleration equal to
A solid cylinder of mass M and radius R rolls down an inclined plane without slipping. The speed of its centre of mass when it reaches the bottom is
Solid cylinders of radii ${{r}_{1}},\,{{r}_{2}}$ and ${{r}_{3}}$ roll down an inclined plane from the same place simultaneously. If ${{r}_{1}}>{{r}_{2}}>{{r}_{3}}$, which one would reach the bottom first
A solid cylinder of radius R and mass M, rolls down on inclined plane without slipping and reaches the bottom with a speed v. The speed would be less than v if we use
A body starts rolling down an inclined plane of length L and height h. This body reaches the bottom of the plane in time t. The relation between L and t is
A hollow cylinder is rolling on an inclined plane, inclined at an angle of ${{30}^{o}}$ to the horizontal. Its speed after travelling a distance of 10 m will be

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