Questions in indefinite-integration

Select	Question
	$\int_{{}}^{{}}{\frac{d\theta }{\sin \theta {{\cos }^{3}}\theta }=}$
	$\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}$
	To evaluate $\int_{{}}^{{}}{{{x}^{3}}{{e}^{3{{x}^{2}}+5}}}dx$, the simplest way is to
	To evaluate $\int_{{}}^{{}}{\frac{{{\sec }^{2}}x}{(1+\tan x)(2+\tan x)}\ dx}$, the most suitable substitution is
	$\int_{{}}^{{}}{\frac{\text{cose}{{\text{c}}^{2}}x}{1+\cot x}dx=}$
	$\int_{{}}^{{}}{\frac{1}{\sqrt{x}}}\sin \sqrt{x}\ dx=$
	$\int_{{}}^{{}}{{{e}^{x}}{{\tan }^{2}}({{e}^{x}})dx=}$
	$\int_{{}}^{{}}{\frac{dx}{{{e}^{-2x}}{{({{e}^{2x}}+1)}^{2}}}=}$
	$\int_{{}}^{{}}{{{\tan }^{4}}x\ dx=}$
	$\int_{{}}^{{}}{\frac{dx}{x\sqrt{1-{{(\log x)}^{2}}}}=}$