Questions in electrochemistry

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Which of the following has highest electrode potential
Electrode potential data are given below : $F{{e}^{3+}}(aq)+{{e}^{-}}\to F{{e}^{-1}}(aq);\,{{E}^{0}}=+0.77\,V$; $A{{l}^{3+}}(aq)+3{{e}^{-}}\to A{{l}^{-1}}(s);\,{{E}^{0}}=-1.66\,V$; $B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\,{{E}^{0}}=+1.08\,V$; Based on the data given above, reducing power of $F{{e}^{2+}}$, $Al$ and $B{{r}^{-}}$ will increase in the order
K, Ca and Li metals may be arranged in the decreasing order of their standard electrode potentials as
$Z{{n}^{2+}}+2{{e}^{-}}\to Zn(s);\,{{E}^{0}}=-0.76$; $F{{e}^{3+}}+{{e}^{-}}\to F{{e}^{2+}};\,{{E}^{0}}=-0.77$; $C{{r}^{3+}}+3{{e}^{-}}\to Cr;\,{{E}^{0}}=-0.79$; ${{H}^{+}}+2{{e}^{-}}\to 1/2{{H}_{2}};\,{{E}^{0}}=0.00$; Strongest reducing agent is
Oxidation and reduction take place in a cell, then its electromotive force will be
$Emf$ of cell $Ni|N{{i}^{2+}}(1.0M)||A{{u}^{3+}}(1.0M)|Au$ (where ${{E}^{0}}$ for $N{{i}^{2+}}|Ni$ is – 0.25 V; ${{E}^{0}}$ for $A{{u}^{3+}}|Au$ is 1.50 V) is
Electrode potential of $Z{{n}^{2+}}/Zn$ is – 0.76 V and that of $C{{u}^{2+}}/Cu$ is + 0.34 V. The emf of the cell constructed between these two electrodes is
The reaction is spontaneous if the cell potential is
Which one among the following is the strongest reducing agent $F{{e}^{2+}}+2{{e}^{-}}\to Fe(-0.44V)$ $N{{i}^{2+}}+2{{e}^{-}}\to Ni\,(-0.25V)$ $S{{n}^{2+}}+2{{e}^{-}}\to Sn\,(-0.14V)$ $F{{e}^{3+}}+{{e}^{-}}\to F{{e}^{2+}}(-0.77V)$
Arrange the following in the order of their decreasing electrode potential Mg, K, Ba, Ca

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