Questions in electrochemistry

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Following are some facts about electrolytic conduction I : ${{\Lambda }_{m}}$ decreases with $\sqrt{C}$ due to increase in interionic attraction between ions II : For weak electrolytes, there is rapid increase in the degree of ionisation with dilution hence interionic attraction decreases and ${{\Lambda }_{m}}$ or ${{\Lambda }_{eq.}}$ increases rapidly in lower concentration range. III :$\Lambda _{m}^{\infty }$ can be obtained by extrapolation to $\sqrt{C}=0$. Correct statements are
For pure water degree of dissociation of water is $1.9\times {{10}^{-9}}$, $\Lambda _{m}^{\infty }({{H}^{+}})=350\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ $\Lambda _{m}^{\infty }(O{{H}^{-}})=200\,S\,c{{m}^{2}}\,mo{{l}^{-1}}$ hence, molar conductance of water is
Equivalent conductance of $BaC{{l}_{2}}$ and HCl are ${{x}_{1}},\,{{x}_{2}}$ and ${{x}_{3}}\,S\,c{{m}^{2}}\,equi{{v}^{-1}}$ at infinite dilution. If specific conductance of saturated $BaS{{O}_{4}}$ solution is of y$S\,c{{m}^{-1}}$, then ${{K}_{sp}}$ of $BaS{{O}_{4}}$ is
Equivalent conductance at infinite dilution of $BaC{{l}_{2}}$ and $HCl$ aq. Solutions are ${{x}_{1}},\,{{x}_{2}}$ and ${{x}_{3}}$ respectively. Equivalent conductance of $BaS{{O}_{4}}$ solution is
The ionic conductance of ${{H}^{+}}$ and $SO_{4}^{2-}$ are 350 and $80\,S\,c{{m}^{2}}\,equivalen{{t}^{-1}}$, hence equivalent conductance $(S\,c{{m}^{2}}\,equivalen{{t}^{-1}})$ and molar conductance $(S\,c{{m}^{2}}\,mo{{l}^{-1}})$ of ${{H}_{2}}S{{O}_{4}}$ will be
Equivalent conductance of saturated $BaS{{O}_{4}}$ is $400\,Oh{{m}^{-1}}\,c{{m}^{2}}\,equi{{v}^{-1}}$ and specific conductance is $8 imes {{10}^{-5}}\,Oh{{m}^{-1}}\,c{{m}^{-1}}$. Hence ${{K}_{sp}}$ of $BaS{{O}_{4}}$ is
The resistance of $0.1 N$ solution of a salt is found to be $2.5\times {{10}^{3}}\,Ohms$. The equivalent conductance of the solution is (cell constant $=1.15\,c{{m}^{-1}})$
Specific conductance of $0.1 M$ sodium chloride solution is $1.06\times {{10}^{-2}}\,Oh{{m}^{-1}}\,c{{m}^{-1}}$. Its molar conductance in $Oh{{m}^{-1}}\,c{{m}^{2}}\,mo{{l}^{-1}}$ is
In the experiment set up for the measurement of emf of a half cell using a reference electrode and a salt bridge, when the salt bridge is removed, the voltage
The reaction $\frac{1}{2}{{H}_{2}}(g)+AgCl(s)\to {{H}^{+}}(aq)+C{{l}^{-}}(aq)+Ag(s)$ occurs in the Galvanic cell

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