Questions in differentiation

Select	Question
	If $y={{\sin }^{-1}}\frac{\sqrt{(1+x)}+\sqrt{(1-x)}}{2}$, then $\frac{dy}{dx}=$
	If$f(x)=x+2,$ then $f'(f(x))$ at x = 4 is
	If $f(x)={{\cot }^{-1}}\left( \frac{{{x}^{x}}-{{x}^{-x}}}{2} \right)\,,$then $f'(1)$ is equal to
	Let $3f(x)-2f(1/x)=x,$ then $f'(2)$is equal to
	$\frac{d}{dx}\left[ {{\sin }^{2}}{{\cot }^{-1}}\left\{ \sqrt{\frac{1-x}{1+x}} \right\} \right]$ equals
	If $y={{\tan }^{-1}}\left( \frac{x}{1+\sqrt{1-{{x}^{2}}}} \right)$, then $\frac{dy}{dx}=$
	Differential coefficient of ${{\cos }^{-1}}(\sqrt{x})$with respect to $\sqrt{(1-x)}$ is
	If $y={{\tan }^{-1}}\left( \frac{x}{\sqrt{1-{{x}^{2}}}} \right)$, then $\frac{dy}{dx}=$
	If $y={{\sin }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)$, then $\frac{dy}{dx}$ equals
	The differential coefficient of ${{\tan }^{-1}}\left( \frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt{1+x}+\sqrt{1-x}} \right)$ is