Questions in differentiation

SelectQuestion
$\frac{d}{{dx}}\left[ {\log \left( {x + \frac{1}{x}} \right)} \right] = $
If $y = {\sin ^{ - 1}}\sqrt x $, then $\frac{{dy}}{{dx}} = $
If $y = {\sin ^{ - 1}}\sqrt {(1 - x)} + {\cos ^{ - 1}}\sqrt x $, then $\frac{{dy}}{{dx}} = $
If $y = {x^n}\log x + x{(\log x)^n}$, then $\frac{{dy}}{{dx}} = $
If $y\sqrt {{x^2} + 1} = \log \left\{ {\sqrt {{x^2} + 1} - x} \right\}$, then$({x^2} + 1)\frac{{dy}}{{dx}} + xy + 1 = $
The derivative of tanx – x with respect to x is
If $f(x) = ({\log _{\cot x}}\tan x){({\log _{\tan x}}\cot x)^{ - 1}},$then $f'(2) = $
If $f(x) = 3{e^{{x^2}}}$,then $f'(x) - 2xf(x) + \frac{1}{3}f(0) - f'(0) = $
If $y = {\log _{\cos x}}\sin x$, then $\frac{{dy}}{{dx}}$is equal to
$\frac{d}{{dx}}\left[ {\log \left\{ {{e^x}{{\left( {\frac{{x + 2}}{{x - 2}}} \right)}^{3/4}}} \right\}} \right]$ equals

View Selected Questions (0)

Back to Categories

Back to Home