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The extremities of a diagonal of a parallelogram are the points $(3,-4)$and $(-6,5)$. If third vertex is $(-2,1)$, then fourth vertex is
(0, –1) and (0, 3) are two opposite vertices of a square. The other two vertices are
If $A(3,\,5),B(-5,\,-4),C(7,\,10)$ are the vertices of a parallelogram, taken in the order, then the co-ordinates of the fourth vertex are
If the point (a, a) are placed in between the lines $|x+y|=4$, then
The three points (–2,2), (8,–2) and (–4, –3) are the vertices of
The points $\left( \frac{a}{\sqrt{3}},a \right),\ \left( \frac{2a}{\sqrt{3}},\,2a \right),\ \left( \frac{a}{\sqrt{3}},\,3a \right)$are the vertices of
The points $(a,b),\ (c,d)$and $\left( \frac{kc+la}{k+l},\,\frac{kd+lb}{k+l} \right)$ are
The points (0, 8/3), (1, 3) and (82, 30) are the vertices of
The points (3a, 0), (0, 3b) and (a, 2b) are
The points $(-a,-b),\ (a,b),\ ({{a}^{2}},ab)$are

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