Questions in circle

SelectQuestion
Consider the circles ${{x}^{2}}+{{(y-1)}^{2}}=$ $9,{{(x-1)}^{2}}+{{y}^{2}}=25$ . They are such that
The locus of centre of the circle which cuts the circles${{x}^{2}}+{{y}^{2}}+2{{g}_{1}}x+2{{f}_{1}}y+{{c}_{1}}=0$ and ${{x}^{2}}+{{y}^{2}}+2{{g}_{2}}x+2{{f}_{2}}y+{{c}_{2}}=0$ orthogonally is
A circle passes through the origin and has its centre on $y=x$ . If it cuts ${{x}^{2}}+{{y}^{2}}-4x-6y+10=0$ orthogonally, then the equation of the circle is
The radical centre of three circles described on the three sides of a triangle as diameter is
The lengths of tangents from a fixed point to three circles of coaxial system are ${{t}_{1}},{{t}_{2}},{{t}_{3}}$ and if P, Q and R be the centres, then $QRt_{1}^{2}+RPt_{2}^{2}+PQt_{3}^{2}$ is equal to
P, Q and R are the centres and ${{r}_{1}},\,\,{{r}_{2}},\,\,{{r}_{3}}$ are the radii respectively of three co-axial circles, then $QRr_{1}^{2}+RP\,r_{2}^{2}+PQr_{3}^{2}$ is equal to
The circle ${{x}^{2}}+{{y}^{2}}+2gx+2fy+c=0$ bisects the circumference of the circle ${{x}^{2}}+{{y}^{2}}+2g'x+2f'y+c'=0$ , if
Circles ${{(x+a)}^{2}}+{{(y+b)}^{2}}={{a}^{2}}$ and ${{(x+\alpha )}^{2}}$ $+{{(y+\beta )}^{2}}=$ ${{\beta }^{2}}$ cut orthogonally, if
The circles ${{x}^{2}}+{{y}^{2}}+4x+6y+3=0$ and $2({{x}^{2}}+{{y}^{2}})+6x+4y+C=0$ will cut orthogonally, if C equals
Any circle through the point of intersection of the lines $x+\sqrt{3}y=1$ and $\sqrt{3}x-y=2$ if intersects these lines at points P and Q, then the angle subtended by the arc PQ at its centre is

View Selected Questions (0)

Back to Categories

Back to Home