Questions in Work, Energy and Power

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	Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear momentums is
	A stationary particle explodes into two particles of a masses m1 and m2 which move in opposite directions with velocities ${v_1}$ and ${v_2}.$ The ratio of their kinetic energies ${E_1}/{E_2}$is
	The kinetic energy of a body of mass 3 kg and momentum 2 Ns is
	A bomb of mass 3.0 Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 80 m/s.The total energy imparted to the two fragments is
	A bullet moving with a speed of 100 $m{s^{ - 1}}$can just penetrate two planks of equal thickness. Then the number of such planks penetrated by the same bullet when the speed is doubled will be
	A particle of mass ${m_1}$ is moving with a velocity ${v_1}$and another particle of mass ${m_2}$is moving with a velocity ${v_2}$. Both of them have the same momentum but their different kinetic energies are ${E_1}$and ${E_2}$respectively. If ${m_1} > {m_2}$ then
	A ball of mass 2kg and another of mass 4kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of
	Four particles given, have same momentum which has maximum kinetic energy
	A body moving with velocity v has momentum and kinetic energy numerically equal. What is the value of v
	If a man increase his speed by 2 m/s , his K.E. is doubled, the original speed of the man is