Questions in Oscillations

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Two masses ${{m}_{1}}$ and ${{m}_{2}}$ are suspended together by a massless spring of constant k. When the masses are in equilibrium, ${{m}_{1}}$ is removed without disturbing the system. Then the angular frequency of oscillation of ${{m}_{2}}$ is
In arrangement given in figure, if the block of mass $m$ is displaced, the frequency is given by Question Image
Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m is suspended from them. The ratio of their frequencies of vertical oscillations will be Question Image
A mass m is suspended from the two coupled springs connected in series. The force constant for springs are ${{K}_{1}}$ and ${{K}_{2}}$. The time period of the suspended mass will be
A spring is stretched by 0.20 m, when a mass of 0.50 kg is suspended. When a mass of 0.25 kg is suspended, then its period of oscillation will be $(g=10m/{{s}^{2}})$
A mass $M$ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period $T$. If the mass is increased by m then the time period becomes $\left( \frac{5}{4}T \right)$. The ratio of $\frac{m}{M}$ is
A spring having a spring constant $K$ is loaded with a mass $m$. The spring is cut into two equal parts and one of these is loaded again with the same mass. The new spring constant is
A weightless spring which has a force constant oscillates with frequency $n$ when a mass $m$ is suspended from it. The spring is cut into two equal halves and a mass $2m$ is suspended from it. The frequency of oscillation will now become
A mass $M$ is suspended from a light spring. An additional mass $m$ added displaces the spring further by a distance $x$. Now the combined mass will oscillate on the spring with period
In the figure, ${{S}_{1}}$ and ${{S}_{2}}$ are identical springs. The oscillation frequency of the mass $m$ is $f$. If one spring is removed, the frequency will become Question Image

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