Questions in Dual Nature of Radiation and Matter

Select	Question
	The de-Broglie wavelength is proportional to
	Particle nature and wave nature of electromagnetic waves and electrons can be shown by
	The de-Broglie wavelength of a particle moving with a velocity $2.25 \times 10^8$ m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is $3 \times 10^8$ m/s)
	According to de-Broglie, the de-Broglie wavelength for electron in an orbit of hydrogen atom is $10^{–9}$ m. The principle quantum number for this electron is
	The speed of an electron having a wavelength of ${10^{ - 10}}m$ is
	The kinetic energy of electron and proton is ${10^{ - 32}}J$. Then the relation between their de-Broglie wavelengths is
	The de-Broglie wavelength of a particle accelerated with 150 volt potential is ${10^{ - 10}}$ m. If it is accelerated by 600 volts p.d., its wavelength will be
	The de-Broglie wavelength associated with a hydrogen molecule moving with a thermal velocity of 3 km/s will be
	When the momentum of a proton is changed by an amount P0, the corresponding change in the de-Broglie wavelength is found to be 0.25%. Then, the original momentum of the proton was
	The de-Broglie wavelength of a neutron at $27^o$ C is $\lambda$. What will be its wavelength at $927^o$ C