Questions in Current Electricity

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A galvanometer can be converted into an ammeter by connecting
A cell of internal resistance $1.5\,\Omega $ and of e.m.f.1.5 volt balances 500 cm on a potentiometer wire. If a wire of $15\,\Omega $ is connected between the balance point and the cell, then the balance point will shift
${10^{ - 3}}amp$ is flowing through a resistance of $1000\,\Omega $. To measure the correct potential difference, the voltmeter is to be used of which the resistance should be
A galvanometer of $100\,\Omega $ resistance gives full scale deflection when 10 mA of current is passed. To convert it into 10 A range ammeter, the resistance of the shunt required will be
$50\,\Omega $ and $100\,\Omega $ resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of $100\,\Omega $ resistance is connected across $100\,\Omega $ resistor, then the reading of the voltmeter will be
A 2 volt battery, a $15\,\Omega $ resistor and a potentiometer of 100 cm length, all are connected in series. If the resistance of potentiometer wire is$5\,\Omega $, then the potential gradient of the potentiometer wire is
An ammeter gives full scale deflection when current of 1.0 A is passed in it. To convert it into 10 A range ammeter, the ratio of its resistance and the shunt resistance will be
By ammeter, which of the following can be measured
The resistance of 1 A ammeter is $0.018\,\Omega $. To convert it into 10 A ammeter, the shunt resistance required will be
For measurement of potential difference, potentiometer is preferred in comparison to voltmeter because

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