Questions in Current Electricity

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	A primary cell has an e.m.f. of 1.5 volts, when short-circuited it gives a current of 3 amperes. The internal resistance of the cell is
	A 50V battery is connected across a 10 ohm resistor. The current is 4.5 amperes. The internal resistance of the battery is
	The potential difference in open circuit for a cell is 2.2 volts. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be
	A new flashlight cell of e.m.f. 1.5 volts gives a current of 15 amps, when connected directly to an ammeter of resistance $0.04\,\Omega $. The internal resistance of cell is
	A cell whose e.m.f. is 2 V and internal resistance is $0.1\,\Omega $, is connected with a resistance of$3.9\,\Omega $. The voltage across the cell terminal will be
	The reading of a high resistance voltmeter when a cell is connected across it is 2.2 V. When the terminals of the cell are also connected to a resistance of $5\,\Omega $ the voltmeter reading drops to 1.8 V. Find the internal resistance of the cell
	When cells are connected in parallel, then
	The internal resistance of a cell depends on
	n identical cells each of e.m.f.E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is
	A cell of internal resistance r is connected to an external resistance R. The current will be maximum in R, if